Power of a Point Solutions

نویسنده

  • Yufei Zhao
چکیده

Solution. Let the common chord extended meet AB at M . Since M lies on the radical axis of Γ1 and Γ2, it has equal powers with respect to the two circles, so MA 2 = MB2. Hence MA = MB. 2. Let C be a point on a semicircle of diameter AB and let D be the midpoint of arc AC. Let E be the projection of D onto the line BC and F the intersection of line AE with the semicircle. Prove that BF bisects the line segment DE.

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تاریخ انتشار 2011